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4t/t^2-25=1/5-t
We move all terms to the left:
4t/t^2-25-(1/5-t)=0
Domain of the equation: t^2!=0
t^2!=0/
t^2!=√0
t!=0
t∈R
Domain of the equation: 5-t)!=0We add all the numbers together, and all the variables
We move all terms containing t to the left, all other terms to the right
-t)!=-5
t!=-5/1
t!=-5
t∈R
4t/t^2-(-1t+1/5)-25=0
We get rid of parentheses
4t/t^2+1t-25-1/5=0
We calculate fractions
(-1t^2)/5t^2+1t+20t/5t^2-25=0
We add all the numbers together, and all the variables
(-1t^2)/5t^2+t+20t/5t^2-25=0
We multiply all the terms by the denominator
(-1t^2)+t*5t^2+20t-25*5t^2=0
We add all the numbers together, and all the variables
(-1t^2)+20t+t*5t^2-25*5t^2=0
Wy multiply elements
(-1t^2)+5t^3-125t^2+20t=0
We get rid of parentheses
-1t^2+5t^3-125t^2+20t=0
We do not support etpression: t^3
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